0=9t^2-80t

Solution for 0=9t^2-80t equation:

0=9t^2-80t

We move all terms to the left:

0-(9t^2-80t)=0

We add all the numbers together, and all the variables

-(9t^2-80t)=0

We get rid of parentheses

-9t^2+80t=0

a = -9; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·(-9)·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*-9}=\frac{-160}{-18}
=8+8/9
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*-9}=\frac{0}{-18}
=0
$